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Tuesday, August 7, 2012

FIFO using Paging and Page Faults in C

Below is a Simple C Language Program Which shows simulation of demand paging & show page faults
according to FIFO replacement

#include<stdio.h>
#include<conio.h>
int frames[]={-1,-1,-1};
int page_found(int pno)
{
int i;
for(i=0;i<3;i++)
if(frames[i]==pno)
   return i;
return -1;
}
void main()
{
int i;
int page_fault;
int p_request[]={9,14,10,11,15,9,11,9,15,10,9,15,10,12,5};
int size=15,page_faults=0;
clrscr();
printf("\n Page No.___Page_Frames");
printf("\n_________________________\n");
for(i=0;i<size;i++)
{
if(page_found(p_request[i]==-1))//next page is not in frame
{
   frames[page_fault%3]=p_request[i];
   page_faults++;
   printf("%4d___%4d%4d%4d\n",p_request[i],frames[0],frames[1],frames[2]);
}
else
printf("\n %4d",p_request[i]);
}
printf("\n_________________________\n");
printf("\n Total Page Faults=%d",page_faults);
getch();
}

Shell Program In C

Here is a Simple Shell Program In C Language which counts the number of chars, words, and Lines Provided in the input.

#include <stdio.h>
#include <conio.h>

void count();

void main(int argc, char *argv[])
{
    char fname[20];
    char option;

    if( argc != 3 )
    {
        printf("Invalid number of arguments");
        return ;
    }
    option = *argv[1];
    strcpy(fname,argv[2]);
    count(fname, option);
} // main

void count( char fname[], char option)

{
    long ccnt, wcnt,lcnt;
    FILE *fp;

    long lflag,wflag;
    int ch;

    fp = fopen(fname,"r");
    if( fp == NULL )
    {
        printf("\nUnable to open a file");
        exit(0);
    }
    ccnt = wcnt = lcnt = 0;
    lflag = wflag = 1;
    ch = fgetc(fp);
    while( ch != EOF )
    {
        ccnt++;
        if( ch == ' ' || ch == '\t')
        {
            lflag = 0;
            if( wflag == 0 )
            {
                wcnt++;
                wflag = 1;
            }
        }
        else
        if( ch == 10 )
        {
            ccnt++;
            lcnt++;
            lflag = 1;
            if( wflag == 0 )
            {
                wcnt++;
                wflag = 1;
            }
        }
        else   // normal
        {
            wflag = 0;
            lflag = 0;
        }
        ch = fgetc(fp);
    } // while

    if( wflag == 0 )
        wcnt++;
    if( lflag == 0 )
        lcnt++;
    switch(option)
    {
        case 'c' :printf("\n char count = %ld\n",ccnt);
                break;
        case 'w' :
                    printf("\n word count = %ld\n",wcnt);
                    break;
        case 'l' :
                    printf("\n line count = %ld\n",lcnt);
    } // switch
} // count

Monday, August 6, 2012

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Sunday, August 5, 2012

GCD and LCM of two numbers

Here is a Simple Program in Php which gives GCD and LCM of two Numbers.

   1) Here is a Simple Html Form to Enter the Two Numbers.

           <html>
<head>
<title>"LCMGCD"</title>
</head>
<body>
<form name="LCMGCD" method="GET" action="lcmgcd.php">
<table width="100%" cellpadding="0" cellspacing="0">
<tr>
<td>
<fieldset>
<ol>
      <li>
          <label>ENTER THE INTEGER NUMBER1:</label>
          <input type="text" name="Num1" value=" ">
      </li>
      <li>
          <label>ENTER THE INTEGER NUMBER2:</label>
          <input type="text" name="Num2" value=" ">
      </li>
      <li>
        <input type="submit" name="LCMGCD" value="submit"><br>
      </li>
</ol>
</fieldset>.
</td>
</tr>
</table>
</form>
</body>
</html>

2) Here is lcmgcd.php for Calculating the two numbers.

        <?php
$n1=$_GET['Num1'];
$n2=$_GET['Num2'];
echo"FIRST NUMBER IS :-> $n1<br>";
echo"SECOND NUMBER IS :-> $n2<br>";
echo"GCD OF 2 NUMBERS IS :-> ".gcd($n1,$n2)."<br>";

function gcd($a,$b)
{
$a1=$a;
$b1=$b;
while($a<>$b)
{
     if($a>$b)
       $a=$a-$b;
     else
       $b=$b-$a;
}
echo"<br>LCM OF 2 NUMBERS IS :-> ".(($a1*$b1)/$a)."<br>";
return $a;

}
?>

Program For Perfect Number

Here is a Simple PHP program to check whether the given number is Perfect or Not.

1) Below in an Html Form to Enter the Number.

     <html>
<head>
<title>PERFECT NUMBER</title>
</head>
<body>
<form name="perfect" method="GET" action="perfect.php">
<table width="100%" cellpadding="0" cellspacing="0" >
<tr>
<td>
<fieldset>
<ol>
    <li>
        <label>ENTER THE NUMBER:</label>
        <input type="text" name="Num" value=" ">
    </li>
    <li>
        <input type="submit" name="calculate" value="submit"><br>
    </li>
</ol>
</fieldset>
</td>
</tr>
</table>
</form>
</body>
</html>

2) Below is the Perfect .php

          <?PHP
$n=$_GET['Num'];
for($i=2,$sum=1;$i<$n;$i++)
{
   if($n%$i==0)
     $sum=(int)$sum+$i;
}
if($sum==$n)
echo"      ENTERED NO. $n IS PERFECT";
else
echo"      ENTERED NO. $n IS NOT PERFECT";
?>

PHP : Palindrome Number Program

Here is a simple PHP program which checks whether the given number is palindrome or not.

1) Here is the form to enter the number.

<html>
    <head>
        <title>INTEGER PALINDROME</title>
    </head>
    <body>
        <table width="100%" cellpadding="0" cellspacing="0">
            <tr>
                <td>
                    <form name="palindrome" method="GET" action="palindrome.php">
                        <fieldset>
                            <ol>
                                <li>
                                    <label>ENTER THE INTEGER NUMBER:</label>
                                    <input type="text" name="Num" value=" ">
                                </li>
                                <li>
                                    <input type="submit" name="check" value="submit"><br>
                                </li>
                            </ol>
                        </fieldset>    
                    </form>
                </td>
            </tr>
        </table>
    </body>
</html>

2) Now here is the Palindrome.php which gets the number and checks whether it is palindrome or not.

<?php
$n = $_GET['Num'];
function intpal($n1)
{
    $sum = 0;
    $nn = $n1;
    while ($nn > 0) {
        $sum = $sum * 10;
        $sum = $sum + $nn % 10;
        if (($nn % 10) <> 0)
            $nn = ceil($nn / 10) - 1;
        else
            $nn = $nn / 10;
    }
    if ($sum == $n1)
        echo"INTEGER $n1 IS Palindrome ";
    else
        echo"INTEGER $n1 IS NOT Palindrome ";
}
if (empty($n)) {
    echo"ENTER VALID INPUT";
    exit;
}
intpal($n);
?>